Solution 1
Python
class Solution:
def checkInclusion(self, s1: str, s2: str) -> bool:
need = Counter(s1)
have = Counter(s2[:len(s1)-1])
i = 0
for c in s2[len(s1)-1:]:
have[c] = have.get(c, 0) + 1
if need == have: return True
have[s2[i]] -= 1
i += 1
return need == have