Solution 1Char Count
class Solution:
def isAnagram(self, s: str, t: str) -> bool:
return Counter(s) == Counter(t)public boolean isAnagram(String s, String t) {
if (s.length() != t.length()) { return false; }
int[] count = new int[26];
for (int i=0; i<s.length(); i++) {
count[s.charAt(i) - 'a']++;
count[t.charAt(i) - 'a']--;
}
for (int i=0; i<26; i++) {
if(count[i] != 0) {
return false;
}
}
return true;
}