Solution 1Char Count

class Solution:
    def isAnagram(self, s: str, t: str) -> bool:
        return Counter(s) == Counter(t)
Leet Code/python.py · L85–88
public boolean isAnagram(String s, String t) {
    if (s.length() != t.length()) { return false; }
    int[] count = new int[26];
    for (int i=0; i<s.length(); i++) {
        count[s.charAt(i) - 'a']++;
        count[t.charAt(i) - 'a']--;
    }
    for (int i=0; i<26; i++) {
        if(count[i] != 0) {
            return false;
        }
    }
    return true;
}
Leet Code/java.java · L17–31